Q. 14.2( 249 Votes )

A 0.24 g sample o

Answer :

(i) Mass of boron in compound = 0.096 g

And, Mass of compound = 0.24 g


So, Percentage of boron =


                                  = 


                                  = 40% (1)


(ii) Mass of oxygen in compound = 0.144 g


And, Mass of compound = 0.24 g


So, Percentage of oxygen =


= 60% (2)


Thus, the percentage composition of the compound is: Boron = 40%; Oxygen = 60%

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