Q. 565.0( 1 Vote )

# <span lang="EN-US

Given

Volume of oxygen = 50cc=50cm3=50

Atmospheric pressure Po=99.4kPa=99.4Pa

Temperature =27=300.15K

Saturation vapor pressure Ps=3.4kPa=3.4Pa

According to question water level in the jar is same as level outside. So

Pressure inside the jar = pressure outside the jar

Pressure outside the jar =atmospheric pressure Po

Pressure inside the jar=Po …. (1)

But

Pressure inside the jar is also = vapor pressure of oxygen+ Saturation vapor pressure

Pressure inside the jar=P+Ps …. (2)

From equation (1) and (2), we can write

Po=P+Ps

P=Po-Ps=99.4-3.4=96Pa

Applying ideal gas equation

PV=nRT

Where V= volume of gas

R=gas constant =8.3JK-1mol-1

T=temperature

n=number of moles of gas

P=pressure of gas.

The number of moles of oxygen collected in the jar is 1.9310-3.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Pure water HC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Find the number oHC Verma - Concepts of Physics Part 2

Consider a gas ofHC Verma - Concepts of Physics Part 2