Answer :
As per the given information
Height of the object is 5 cms
Focal length f is 10 cms
Object distance u = 25 cms
Image distance v= ?
Height of the image h = ?
⇒ 
⇒ 
⇒ 
V = 50/3 =16.66 cms
The image formed will be real and inverted on the other side of the lens at a distance of 16.66 cms from its optical centre.
Now
m= v/u
Where h2 is the height of the object
⇒ h2 = 3.33cms
Therefore from above we can conclude an inverted image of 3.33cm will be formed.
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