Answer :

As per the given information

Height of the object is 5 cms

Focal length f is 10 cms

Object distance u = 25 cms

Image distance v= ?

Height of the image h = ?

⇒

⇒

⇒

V = 50/3 =16.66 cms

The image formed will be real and inverted on the other side of the lens at a distance of 16.66 cms from its optical centre.

Now

m= v/u

Where h_{2} is the height of the object

⇒ h_{2} = 3.33cms

Therefore from above we can conclude an inverted image of 3.33cm will be formed.

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