Q. 2

3.42 of sucrose is dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are:
A. 6.68 x 1023

B. 6.09 x 1022

C. 6.022 x 1023

D. 6.022 x 1021

Answer :

Molar mass of sucrose = C12H22O11


= 12× 12 + 1× 22 + 16 × 11 = 342g/mol




Number of moles = 0.01


Sucrose (C12H22O11) contains 11 oxygen atoms


11 × 6.022 × 1023


For 0.01 moles of sucrose


0.01 × 11 × 6.022 × 1023= 6.6 × 1022


Now, Molar mass of water = H2O = 2× 1 + 16 = 18g/mol




Number of moles = 1


Sucrose (H2O) contains 1 oxygen atom = 6.022 × 1023


For 1 mole of water = 6.022 × 1023


Now, add the both values: 6.6 × 1022+ 6.022 × 1023


We get 6.68 × 1023 atoms. Hence, the option (a) is correct.

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