Q. 2

# 3.42 of sucrose is dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are:A. 6.68 x 1023B. 6.09 x 1022C. 6.022 x 1023D. 6.022 x 1021

Molar mass of sucrose = C12H22O11

= 12× 12 + 1× 22 + 16 × 11 = 342g/mol

Number of moles = 0.01

Sucrose (C12H22O11) contains 11 oxygen atoms

11 × 6.022 × 1023

For 0.01 moles of sucrose

0.01 × 11 × 6.022 × 1023= 6.6 × 1022

Now, Molar mass of water = H2O = 2× 1 + 16 = 18g/mol

Number of moles = 1

Sucrose (H2O) contains 1 oxygen atom = 6.022 × 1023

For 1 mole of water = 6.022 × 1023

Now, add the both values: 6.6 × 1022+ 6.022 × 1023

We get 6.68 × 1023 atoms. Hence, the option (a) is correct.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
NCERT Exemplar | Atoms and Molecules48 mins
Types of Bonding29 mins
Mastering in Valency33 mins
Quiz | Solve Imp. Qs. on Ions,Molecules and Compounds26 mins
Champ Quiz | Are you a Master of Mole Concept ?35 mins
Quiz on Be a Master of Mole Concept in 30 Minutes!35 mins
Champ Quiz | Writing Complex Chemical Formulae34 mins
Genius Quiz | Test Your Knowledge on Chemical Formulae33 mins
Be a Master of Mole Concept Within 45 Minutes2 mins
Quiz | Mastering in Finding The Valency27 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses