# 100 g of liquid A

Given-

Mass of liquid A, WA = 100g, Molar mass, MA = 140 g mol-1

Mass of liquid B, WB = 1000 g, Molar mass, MB = 180 g mol-1

Using the formula below calculate the no. of moles in liquid A and B.

Number of moles of liquid A, MA = 100/140 = 0.714 mol-1

Number of moles of liquid B, MB = 1000/ 180 = 5.556 mol-1

Using the formula,

,

we calculate the mole fraction of liquids A and B.

Mole fraction of A,

Mole fraction of B,

Vapour pressure of pure liquid B, PoB = 500 torr (given)

According to Henry`s law,

Having given the total vapour pressure of the solution, Ptotal = 475 torr,

Using Henry`s law again to get the vapour pressure of pure liquid A,

Thus, the vapour pressure of pure liquid A = 280.7 torr and

vapour pressure of liquid A in the solution = 32 torr

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