# (-1,3) to the line 3x-4y-16=0

The equation of the straight line perpendicular to the given straight line

3x-4y-16=0 (1)

Will be of the form 4x+3y+k=0.

Since, (-1,3) is a point on it, 4(-1)+3(3)+k=0

Therefore k = -5

Substituting in the equation above, the equation of the straight line passing through(-1,3) and perpendicular to the equation 3x-4y=16 is

4x+3y-5=0 …(2)

Solving equation (1) and equation (2)

4x+3y=5

3x-4y=16

Therefore the foot of the perpendicular is = ( )

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Various Forms of Equations of line45 mins  Parametric Equations of Straight line48 mins  Slope, inclination and angle between two lines48 mins  Interactive Quiz on Equations of line23 mins  Straight line | Analyse your learning through quiz56 mins  General Equation of a line43 mins  Motion in a Straight Line - 0665 mins  Motion in a Straight Line - 0556 mins  Motion in a Straight Line - 0372 mins  Understand The Interesting Concept Of Relative velocity in 1- Dimension44 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 